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Linear Inequalities

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Summary

Chapter 5: Linear Inequalities

Summary

  • Linear inequalities involve expressions with inequality signs: <, >, ≤, ≥.
  • They can be solved for different sets of numbers: natural numbers, integers, and real numbers.
  • Graphical representation of solutions is essential for understanding.
  • Rules for solving inequalities include adding/subtracting equal numbers and multiplying/dividing by positive numbers without changing the inequality sign, but reversing it when multiplying/dividing by negative numbers.
  • Examples include solving inequalities for average marks, costs, and temperature ranges.

Key Examples

  • Example 1: Solve 30x < 200 for natural numbers: {1, 2, 3, 4, 5, 6}.
  • Example 2: Solve 5x - 3 < 3x + 1 for integers: {..., -4, -3, -2, -1, 0, 1}.
  • Example 3: Solve 4x + 3 < 6x + 7: x > -2.
  • Example 4: Solve 7x + 3 < 5x + 9: x < 3.

Important Diagrams

  • Number Line Representation:
    • Solid dot indicates included values.
    • Open circle indicates excluded values.
    • Arrows indicate ranges extending to infinity.

Common Mistakes & Exam Tips

  • Mistake: Forgetting to reverse the inequality sign when multiplying/dividing by a negative number.
  • Tip: Always check the solution by substituting values back into the original inequality.

Learning Objectives

Learning Objectives

  • Understand the concept of linear inequalities in one and two variables.
  • Solve linear inequalities for different types of numbers (natural, integers, real).
  • Graphically represent the solutions of linear inequalities on a number line.
  • Apply linear inequalities to real-world problems, such as budgeting and averages.
  • Distinguish between strict and slack inequalities.
  • Identify and solve systems of linear inequalities.

Detailed Notes

Chapter 5: Linear Inequalities

5.1 Introduction

  • Study of linear inequalities in one and two variables.
  • Useful in various fields: science, mathematics, statistics, economics, psychology.

5.2 Inequalities

Definition

  • Two real numbers or algebraic expressions related by symbols: <, >, ≤, or ≥ form an inequality.
  • Examples:
    • Numerical inequalities: 3 < 5; 7 > 5
    • Literal inequalities: x < 5; y > 2; x ≥ 3; y ≤ 4
    • Double inequalities: 3 < x < 5

Examples of Inequalities

  1. Strict Inequalities:
    • ax + b < 0
    • ax + b > 0
  2. Slack Inequalities:
    • ax + b ≤ 0
    • ax + b ≥ 0
  3. Linear Inequalities in Two Variables:
    • ax + by < c
    • ax + by > c

Examples of Problem Solving

  • Example 1: Ravi's rice purchase
    • Total amount spent: ₹30x < 200
  • Example 2: Reshma's purchase of registers and pens
    • Total amount spent: 40x + 20y ≤ 120

5.3 Algebraic Solutions of Linear Inequalities in One Variable and their Graphical Representation

Solving Inequalities

  • Example: Solve 4x + 3 < 6x + 7
    • Solution: x > -2 (solution set: (-2, ∞))
  • Example: Solve 5 - 2x ≤ 8
    • Solution: x ≥ 8 (solution set: [8, ∞))

Graphical Representation

  • Fig 5.1: Number line showing solutions of inequalities.
  • Fig 5.2: Graphical representation of solutions for x < 3.

5.4 Miscellaneous Examples

  • Example 9: Solve -8 ≤ 5x - 3 < 7
    • Solution: -1 ≤ x < 2
  • Example 10: Solve the system of inequalities: 3x - 7 < 5 + x < 11 - 5x
    • Solution: 2 ≤ x < 6

Important Diagrams

  • Diagram 1: Number line representing x < 3 (open circle at 3).
  • Diagram 2: Number line representing x ≥ 1 (closed dot at 1).

Conclusion

  • Linear inequalities provide a framework for solving various real-world problems through algebraic expressions and graphical representations.

Exam Tips & Common Mistakes

Common Mistakes and Exam Tips for Linear Inequalities

Common Pitfalls

  • Misinterpreting Inequalities: Students often confuse the symbols for inequalities (e.g., using > instead of <). Always double-check the direction of the inequality sign.
  • Ignoring the Domain: When solving inequalities, it's crucial to consider the specified domain (natural numbers, integers, real numbers). Solutions can vary significantly based on this.
  • Incorrectly Applying Rules: When multiplying or dividing by negative numbers, remember to reverse the inequality sign. This is a common mistake that can lead to incorrect solutions.

Tips for Success

  • Graphical Representation: Always represent your solutions on a number line. This visual aid can help you understand the range of solutions better and avoid mistakes.
  • Check Your Solutions: After finding the solutions, substitute them back into the original inequality to verify their correctness.
  • Practice with Different Domains: Solve inequalities under different conditions (natural numbers, integers, real numbers) to become familiar with how solutions change.
  • Use Systematic Approaches: Instead of trial and error, apply systematic techniques for solving inequalities to save time and reduce errors.

Practice & Assessment

Multiple Choice Questions

A.

60

B.

70

C.

65

D.

75
Correct Answer: B

Solution:

Let xx be the marks obtained in the annual examination. Then, 62+48+x360\frac{62 + 48 + x}{3} \geq 60. Solving, we get x70x \geq 70.

A.

6

B.

5

C.

7

D.

4
Correct Answer: B

Solution:

The inequality is 30x<20030x < 200. Solving for xx, we get x<20030=2036.67x < \frac{200}{30} = \frac{20}{3} \approx 6.67. Since xx must be a whole number, the maximum number of packets Ravi can buy is 6.

A.

(1, 3)

B.

(3, 5)

C.

(5, 7)

D.

(7, 9)
Correct Answer: D

Solution:

Let the integers be xx and x+2x+2. We have x+(x+2)>11x + (x + 2) > 11. Solving gives 2x+2>112x + 2 > 11, so x>4.5x > 4.5. The pairs are (5, 7) and (7, 9), but only (7, 9) is smaller than 10.

A.

500 litres

B.

750 litres

C.

1000 litres

D.

1500 litres
Correct Answer: B

Solution:

Let xx be the litres of water added. The new total volume is 1125+x1125 + x. The new acid concentration is 0.45×11251125+x\frac{0.45 \times 1125}{1125 + x}. We need 0.25<0.45×11251125+x<0.300.25 < \frac{0.45 \times 1125}{1125 + x} < 0.30. Solving these inequalities gives 750<x<2250750 < x < 2250. Therefore, 750 litres of water should be added.

A.

70

B.

72

C.

68

D.

65
Correct Answer: A

Solution:

To find the minimum score, solve 62+48+x360\frac{62 + 48 + x}{3} \geq 60, which simplifies to x70x \geq 70.

A.

40x+20y12040x + 20y \leq 120

B.

40x+20y<12040x + 20y < 120

C.

40x+20y12040x + 20y \geq 120

D.

40x+20y>12040x + 20y > 120
Correct Answer: A

Solution:

The inequality representing her spending limit is 40x+20y12040x + 20y \leq 120 because she cannot spend more than ₹120.

A.

1, 2, 3, 4

B.

1, 2, 3

C.

1, 2, 3, 4, 5

D.

1, 2
Correct Answer: A

Solution:

Dividing both sides by 24, we get x<100244.17x < \frac{100}{24} \approx 4.17. Therefore, the natural numbers satisfying the inequality are 1, 2, 3, and 4.

A.

2

B.

1

C.

3

D.

4
Correct Answer: A

Solution:

After buying 2 registers, Reshma spends ₹80 (2 x 40). She has ₹40 left, which allows her to buy 2 pens (40/20 = 2).

A.

(6, 8), (8, 10)

B.

(6, 8), (8, 10), (10, 12)

C.

(6, 8), (8, 10), (10, 12), (12, 14)

D.

(8, 10), (10, 12)
Correct Answer: A

Solution:

Let the integers be xx and x+2x+2. Then, x>5x > 5 and x+(x+2)<23x + (x + 2) < 23. Solving, we get 6<x<10.56 < x < 10.5. Thus, the pairs are (6, 8) and (8, 10).

A.

92

B.

90

C.

91

D.

93
Correct Answer: D

Solution:

The total marks needed for an average of 90 is 450. The sum of the first four scores is 368. Therefore, she needs at least 450 - 368 = 82 in the fifth exam.

A.

x<2x < 2

B.

x>2x > 2

C.

x2x \leq 2

D.

x2x \geq 2
Correct Answer: A

Solution:

Rearranging the inequality gives 5x3<3x+12x<4x<25x - 3 < 3x + 1 \Rightarrow 2x < 4 \Rightarrow x < 2. Therefore, the solution is x<2x < 2.

A.

35

B.

45

C.

50

D.

55
Correct Answer: C

Solution:

Let xx be the marks obtained in the third test. The average is 70+75+x360\frac{70 + 75 + x}{3} \geq 60. Solving gives 145+x180145 + x \geq 180, so x35x \geq 35.

A.

9.6 to 16.8

B.

10 to 14

C.

8 to 15

D.

11 to 17
Correct Answer: A

Solution:

For 80IQ14080 \leq IQ \leq 140, we have 80MA12×10014080 \leq \frac{MA}{12} \times 100 \leq 140. Solving, 9.6MA16.89.6 \leq MA \leq 16.8.

A.

x<2.5x < -2.5

B.

x>2.5x > -2.5

C.

x<3x < -3

D.

x>3x > -3
Correct Answer: A

Solution:

Dividing both sides by -12 and reversing the inequality sign, we get x<2.5x < -2.5.

A.

320 litres

B.

640 litres

C.

960 litres

D.

1280 litres
Correct Answer: B

Solution:

Let x be the litres of 2% solution added. The inequality becomes 4 < (8*640 + 2x)/(640 + x) < 6. Solving gives x = 640 litres.

A.

20°C to 25°C

B.

22°C to 25°C

C.

18°C to 24°C

D.

19°C to 23°C
Correct Answer: A

Solution:

Using the conversion formula F=95C+32F = \frac{9}{5}C + 32, we solve 6895C+327768 \leq \frac{9}{5}C + 32 \leq 77. Solving these inequalities gives 20C2520 \leq C \leq 25.

A.

20 cm

B.

21 cm

C.

22 cm

D.

23 cm
Correct Answer: B

Solution:

Let the shortest length be xx. Then the second length is x+3x + 3 and the third length is 2x2x. The total length is x+(x+3)+2x91x + (x + 3) + 2x \leq 91. Solving, 4x+3914x88x224x + 3 \leq 91 \Rightarrow 4x \leq 88 \Rightarrow x \leq 22. Therefore, the maximum possible length of the shortest board is 22 cm.

A.

5 cm

B.

6 cm

C.

7 cm

D.

8 cm
Correct Answer: C

Solution:

Let the shortest side be xx. Then the longest side is 3x3x and the third side is 3x23x - 2. The perimeter is x+3x+(3x2)61x + 3x + (3x - 2) \geq 61. Solving, 7x2617x63x97x - 2 \geq 61 \Rightarrow 7x \geq 63 \Rightarrow x \geq 9. Therefore, the minimum length of the shortest side is 9 cm.

A.

2x<42 \leq x < 4

B.

3x<53 \leq x < 5

C.

4x<64 \leq x < 6

D.

1x<31 \leq x < 3
Correct Answer: A

Solution:

First, solve 63(2x4)6 \leq 3(2x - 4): 66x126 \leq 6x - 12, or 186x18 \leq 6x, giving x3x \geq 3. Next, solve 3(2x4)<123(2x - 4) < 12: 6x12<126x - 12 < 12, or 6x<246x < 24, giving x<4x < 4. Combining, 3x<43 \leq x < 4. Therefore, the solution is 2x<42 \leq x < 4.

True or False

Correct Answer: True

Solution:

Solving the inequality 5x3<3x5x - 3 < 3x gives x<2x < 2. Therefore, integer solutions are x=4,3,2,1,0,1x = -4, -3, -2, -1, 0, 1.

Correct Answer: False

Solution:

Let the shortest length be xx. Then, the lengths are xx, x+3x + 3, and 2x2x. The total length is x+(x+3)+2x91x + (x + 3) + 2x \leq 91, simplifying to 4x+3914x + 3 \leq 91, or 4x884x \leq 88, giving x22x \leq 22. Additionally, for the third piece to be at least 5 cm longer than the second, 2xx+3+52x \geq x + 3 + 5, simplifying to x8x \geq 8. Therefore, xx must be between 8 and 22, so 20 cm is possible.

Correct Answer: True

Solution:

Let the shortest side be xx. Then the longest side is 3x3x and the third side is 3x23x - 2. The perimeter is x+3x+(3x2)=7x2x + 3x + (3x - 2) = 7x - 2. Setting 7x2617x - 2 \geq 61 gives 7x637x \geq 63, so x9x \geq 9.

Correct Answer: False

Solution:

Solving the inequality 3x7<5+x3x - 7 < 5 + x gives 2x<122x < 12, so x<6x < 6. The solution set does not include x6x \geq 6.

Correct Answer: True

Solution:

By adding a 2% solution to the 8% solution, the concentration can be adjusted to be more than 4% but less than 6%.

Correct Answer: False

Solution:

Solving 12x>30-12x > 30 gives x<2.5x < -2.5. However, there are no natural numbers that satisfy this inequality.

Correct Answer: True

Solution:

To achieve a boric acid content between 4% and 6%, the amount of 2% solution added must satisfy the inequality for the resulting mixture's concentration. Solving this inequality confirms the possibility.

Correct Answer: True

Solution:

When both sides of an inequality are multiplied or divided by a negative number, the inequality sign must be reversed to maintain the truth of the statement.

Correct Answer: True

Solution:

Using the formula IQ=MACA×100IQ = \frac{MA}{CA} \times 100, for CA = 12, the mental age MA ranges from 9.6 to 16.8 years.

Correct Answer: True

Solution:

Solving 12x>30-12x > 30 gives x<2.5x < -2.5. Since natural numbers are positive integers, there are no natural numbers that satisfy this inequality.

Correct Answer: True

Solution:

Solving 30x<20030x < 200 gives x<20030=203x < \frac{200}{30} = \frac{20}{3}. The integer solutions are x=3,2,1,0,1,2,3,4,5,6x = -3, -2, -1, 0, 1, 2, 3, 4, 5, 6.

Correct Answer: False

Solution:

The average of five exams must be at least 90. So, 87+92+94+95+x590\frac{87 + 92 + 94 + 95 + x}{5} \geq 90. Solving gives x92x \geq 92. However, the correct calculation shows x92x \geq 92 is needed, making the statement true.

Correct Answer: True

Solution:

The IQ formula is IQ=MACA×100IQ = \frac{MA}{CA} \times 100. For a 12-year-old, 80MA12×10014080 \leq \frac{MA}{12} \times 100 \leq 140 simplifies to 9.6MA16.89.6 \leq MA \leq 16.8.

Correct Answer: False

Solution:

For the inequality 30x<20030x < 200, the natural number solutions are 1 through 6. For x=7x = 7, 30×7=21030 \times 7 = 210, which is not less than 200.

Correct Answer: True

Solution:

For the inequality 30x<20030x < 200, when xx is an integer, the values that satisfy the inequality are 3,2,1,0,1,2,3,4,5,6-3, -2, -1, 0, 1, 2, 3, 4, 5, 6. This is because xx must be less than 20/320/3.

Correct Answer: False

Solution:

Solving 12x>30-12x > 30 gives x<2.5x < -2.5. Since natural numbers are positive, there are no natural number solutions.

Correct Answer: False

Solution:

Let the shortest piece be xx. Then the second piece is x+3x + 3 and the third is 2x2x. The condition x+(x+3)+2x91x + (x + 3) + 2x \leq 91 gives 4x+3914x + 3 \leq 91, so x22x \leq 22. Also, 2x(x+3)+52x \geq (x + 3) + 5 gives x8x \geq 8. Thus, 8x228 \leq x \leq 22, so the shortest piece can be as small as 8 cm.

Correct Answer: True

Solution:

Solving the inequality 3x7<5+x3x - 7 < 5 + x gives 2x<122x < 12, which simplifies to x<6x < 6. Thus, the solution is x<6x < 6.

Correct Answer: False

Solution:

When both sides of an inequality are multiplied (or divided) by a negative number, the inequality sign is reversed.

Correct Answer: True

Solution:

Using the formula IQ=MACA×100\text{IQ} = \frac{\text{MA}}{\text{CA}} \times 100, where CA is 12, the range for MA is calculated as 80×12100MA140×12100\frac{80 \times 12}{100} \leq \text{MA} \leq \frac{140 \times 12}{100}, resulting in 9.6MA16.89.6 \leq \text{MA} \leq 16.8.

Correct Answer: True

Solution:

Using the formula IQ=MACA×100\text{IQ} = \frac{\text{MA}}{\text{CA}} \times 100, where MA is mental age and CA is chronological age, we have 80MA12×10014080 \leq \frac{\text{MA}}{12} \times 100 \leq 140. Solving for MA gives 9.6MA16.89.6 \leq \text{MA} \leq 16.8.

Correct Answer: True

Solution:

According to Rule 1, equal numbers may be added to (or subtracted from) both sides of an inequality without affecting the sign of inequality.

Correct Answer: True

Solution:

Using the conversion formula F=95C+32F = \frac{9}{5}C + 32, we can convert 68°F to 20°C and 77°F to 25°C.

Correct Answer: False

Solution:

The integer solutions for the inequality 30x < 200 are -3, -2, -1, 0, 1, 2, 3, 4, 5, and 6.

Correct Answer: True

Solution:

Solving 12x>30-12x > 30 gives x<2.5x < -2.5. The integer solutions are all integers less than -2, including -3.

Correct Answer: True

Solution:

The IQ formula is given by IQ=MACA×100IQ = \frac{MA}{CA} \times 100. For a chronological age (CA) of 12, the mental age (MA) must satisfy 80MA12×10014080 \leq \frac{MA}{12} \times 100 \leq 140. Solving gives 9.6MA16.89.6 \leq MA \leq 16.8.

Correct Answer: False

Solution:

The inequality 12x>30-12x > 30 simplifies to x<52x < -\frac{5}{2}. Since natural numbers are positive, there are no natural number solutions.

Correct Answer: True

Solution:

The inequality is 30x<20030x < 200. Solving for xx, we get x<20030=2036.67x < \frac{200}{30} = \frac{20}{3} \approx 6.67. Since xx must be a whole number, Ravi can buy at most 6 packets.

Correct Answer: True

Solution:

The student needs to score at least 70 in the third exam to achieve an average of 60, as calculated by 62+48+x360\frac{62 + 48 + x}{3} \geq 60, which simplifies to x70x \geq 70.

Correct Answer: True

Solution:

Ravi has ₹200 and each packet costs ₹30. The inequality 30x<20030x < 200 correctly represents the scenario where xx is the number of packets he can buy.

Correct Answer: True

Solution:

Solving 3x7<5+x3x - 7 < 5 + x gives 3xx<5+73x - x < 5 + 7, leading to 2x<122x < 12, so x<6x < 6.

Correct Answer: True

Solution:

When both sides of an inequality are multiplied or divided by a negative number, the direction of the inequality sign is reversed to maintain the truth of the statement.

Correct Answer: True

Solution:

Using the conversion formula F=95C+32F = \frac{9}{5}C + 32, converting 68°F gives C=59(6832)=20°CC = \frac{5}{9}(68 - 32) = 20°C, and 77°F gives C=59(7732)=25°CC = \frac{5}{9}(77 - 32) = 25°C. Thus, the range is 20°C to 25°C.

Correct Answer: True

Solution:

The inequality 120<x<300120 < x < 300 directly describes the condition that the solution has more than 120 liters but less than 300 liters.

Correct Answer: False

Solution:

Solving the inequality gives 2x<42x < 4 or x<2x < 2. Therefore, x=2x = 2 is not included in the solution set.

Correct Answer: True

Solution:

When solving 30x<20030x < 200 for natural numbers, dividing both sides by 30 gives x<20030=203x < \frac{200}{30} = \frac{20}{3}. The natural numbers less than 203\frac{20}{3} are 1,2,3,4,5,61, 2, 3, 4, 5, 6.

Correct Answer: True

Solution:

Dividing both sides by 30 gives x<20030x < \frac{200}{30}, which simplifies to x<6.67x < 6.67. Therefore, the natural numbers satisfying this inequality are 1, 2, 3, 4, 5, and 6.

Correct Answer: True

Solution:

According to Rule 1, equal numbers may be added to (or subtracted from) both sides of an inequality without affecting the sign of the inequality.

Correct Answer: True

Solution:

Solving 12x>30-12x > 30 gives x<3012=2.5x < -\frac{30}{12} = -2.5. Thus, xx can be any integer less than -2.5, such as -3, -4, etc.

Correct Answer: True

Solution:

Ravi can buy rice packets such that 30x<20030x < 200. Solving gives x<20030=203x < \frac{200}{30} = \frac{20}{3}. Thus, he can buy at most 6 packets.

Correct Answer: False

Solution:

Solving 3x7<5+x3x - 7 < 5 + x gives 2x<122x < 12, hence x<6x < 6. The solution does not include x2x \geq 2.

Correct Answer: True

Solution:

The solution to the inequality 5x - 3 < 3x + 1 is x < 2, which includes all real numbers less than 2.

Correct Answer: True

Solution:

If x is the smaller odd number, then x + (x + 2) < 40. Solving gives 10 < x < 19, so pairs like (11, 13) and (13, 15) satisfy the condition.

Correct Answer: True

Solution:

Solving 2x+2<402x + 2 < 40 gives x<19x < 19. If xx is an odd number greater than 10, the possible values are 11, 13, 15, and 17.

Correct Answer: True

Solution:

The inequality is 62+48+x360\frac{62 + 48 + x}{3} \geq 60. Solving gives x70x \geq 70.

Correct Answer: True

Solution:

Using the conversion formula F=95C+32F = \frac{9}{5}C + 32, convert 68°F and 77°F to Celsius: C=59(6832)=20C = \frac{5}{9}(68 - 32) = 20 and C=59(7732)=25C = \frac{5}{9}(77 - 32) = 25. Thus, the temperature range in Celsius is 20°C to 25°C.

Correct Answer: True

Solution:

According to Rule 1, equal numbers may be added to (or subtracted from) both sides of an inequality without affecting the sign of inequality.

Correct Answer: False

Solution:

When x is a natural number, the solution set is {1, 2, 3, 4, 5, 6}. When x is an integer, the solution set is {-3, -2, -1, 0, 1, 2, 3, 4, 5, 6}.

Correct Answer: True

Solution:

The student needs at least 70 because 62+48+x360\frac{62 + 48 + x}{3} \geq 60 simplifies to 110+x180110 + x \geq 180, leading to x70x \geq 70.

Correct Answer: False

Solution:

Let the shortest side be xx. Then the longest side is 3x3x and the third side is 3x23x - 2. The perimeter is x+3x+(3x2)=7x2x + 3x + (3x - 2) = 7x - 2. Solving 7x2617x - 2 \geq 61 gives x9x \geq 9.

Correct Answer: True

Solution:

Solving the inequality 5x3<3x+15x - 3 < 3x + 1 gives 2x<42x < 4, or x<2x < 2. The integer solutions include x=0,1x = 0, 1.

Correct Answer: True

Solution:

Dividing both sides by 30, we get x<20030=203x < \frac{200}{30} = \frac{20}{3}. The natural numbers less than 203\frac{20}{3} are 1, 2, 3, 4, 5, and 6.

Correct Answer: False

Solution:

When both sides of an inequality are multiplied (or divided) by a negative number, the inequality sign is reversed.

Correct Answer: True

Solution:

Solving the inequality 5x3<3x+15x - 3 < 3x + 1 gives 2x<42x < 4, which simplifies to x<2x < 2. Therefore, the solution for xx when xx is a real number is x<2x < 2.

Correct Answer: False

Solution:

Rearranging the inequality gives 4x5x<734x - 5x < 7 - 3, which simplifies to x<4-x < 4. Multiplying both sides by -1 reverses the inequality, resulting in x>4x > -4.

Correct Answer: True

Solution:

To find the minimum score in the annual exam, we set up the inequality: 62+48+x360\frac{62 + 48 + x}{3} \geq 60. Solving gives 110+x180110 + x \geq 180, thus x70x \geq 70.

Correct Answer: True

Solution:

Rule 2 states that when both sides of an inequality are multiplied or divided by a negative number, the sign of inequality is reversed.

Correct Answer: True

Solution:

Let xx be the litres of 2% solution added to 640 litres of 8% solution. The inequality is 8×640+2x640+x\frac{8 \times 640 + 2x}{640 + x} must be between 4% and 6%. Solving gives the range of xx that satisfies the condition.

Correct Answer: True

Solution:

The inequality is 62+48+x360\frac{62 + 48 + x}{3} \geq 60, which simplifies to 110+x180110 + x \geq 180, giving x70x \geq 70.

Correct Answer: False

Solution:

For the inequality 5x3<3x5x - 3 < 3x, solving gives 2x<32x < 3, which means x<1.5x < 1.5. Therefore, the integer solutions are x=0,1x = 0, 1.

Correct Answer: True

Solution:

To achieve an acid content between 25% and 30%, the resulting mixture must be diluted with a certain amount of water. Solving the inequality for the amount of water added shows that it must be between 600 and 900 liters.

Correct Answer: True

Solution:

If the longest side is 3 times the shortest side and the third side is 2 cm shorter than the longest, the perimeter can be at least 61 cm if the shortest side is at least 12 cm.

Correct Answer: False

Solution:

The inequality is 40x+20y12040x + 20y \leq 120. If she buys 2 registers, 40(2)+20y12040(2) + 20y \leq 120 simplifies to 80+20y12080 + 20y \leq 120, which gives y2y \leq 2. Thus, she can buy 2 registers and 2 pens.